Science+Experiment

=Scientific Method Template =
 * Topic:** Dry Ice/Chemical Reaction


 * Question:**What happens when you drop dry ice in hot water?


 * Background Information:**Dry ice sublimates, changing directly to a gas at atmospheric pressure. Its sublimation and deposition point is -78.5 °C (-109.3 °F). Its enthalpy of sublimation at -78.5 °C (-109.3 °F) is 571 kg (245.5 BTU/lb). Dry ice density is usually between 1.2 and 1.6 kg. The low temperature and direct sublimation to a gas makes dry ice an effective coolant, since it is colder than water or ice and leaves no moisture as it changes state. Dry ice can carbonate food that is nearby.


 * Hypothesis:** I think nothing will happen.


 * Procedure:**
 * 1) Get 1 pellet of dry ice.
 * 2) Get a bowl of water and heat it up in the microwave for 2 minutes.
 * 3) Get a pair of tongs to put the dry ice in the bowl. (CAUTION: Do **not** touch dry ice with bare hands. Can cause skin damage.)
 * 4) Take the dry ice and put it in the bowl of hot water.
 * 5) Wait a little bit and see if anything happens. I prefer you keep a window open so your room won't be filled with fog.
 * Materials:**
 * Dry Ice pellets
 * Bowl of hot water
 * Pencil
 * Paper
 * Tongs
 * Hot Pad


 * Experiment:**


 * Data/Results:**

My hypothesis was that if I drop a piece of dry ice in a bowl of hot water nothing will happen.My hypothesis was wrong.. When I dropped the dry ice in hot water, my whole room was full of fog and I had to open my window to get all the fog out.
 * Conclusion:**